Calculate the kinetic energy required to accelerate a proton from a rest position to 0.9999c. The mass of the proton is 1.67x10-27
Find the ratio of kinetic energy to the energy of a proton at rest
Erest = mc2
Ek = mc2/√(1-v2/c2)
The Attempt at a Solution
Ok So calculating the rest energy is easy
= 1.503x10-10/ 0.0141418
= 1x10 -8 J
This doesn't seem like a lot of energy to accelerate something to almost light speed I feel like I am missing something...
even when using Etotal =Erest+EK I get 1x10-8 J
can someone point out my mistake?
Ratio of kinetic energy to rest energy is
1.503x10-10 / 1x10-8
= 1.503 % of the energy is kinetic energy ? ( really unsure about this)
Thanks! Happy monday !