Calculate the moments Mx, My and the center of mass

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SUMMARY

The discussion focuses on calculating the moments Mx and My, specifically in relation to the line equation derived from the point (4, 3). The correct equation of the line is established as y = (3/4)x, which represents the slope of the line passing through the origin and the point (4, 3). Participants clarify the importance of proper equation formatting and the significance of identifying the correct function g(x) in this context.

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huybinhs
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Homework Statement



2010-10-20_2217.png



2. The attempt at a solution

I'm working on #49 ONLY.

I know the top line equation is f(x) = x

but I need to find the g(x), so how can I find with the point is given (4,3). Please help!
 
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huybinhs said:

Homework Statement



2010-10-20_2217.png



2. The attempt at a solution

I'm working on #49 ONLY.

I know the top line equation is f(x) = x
No, it isn't. How could it be, if it goes through (4, 3)?
huybinhs said:
but I need to find the g(x), so how can I find with the point is given (4,3). Please help!
What is g(x) supposed to represent? I am assuming that what you are calling f(x) is the line through (0, 0) and (4, 3).
 
Mark44 said:
No, it isn't. How could it be, if it goes through (4, 3)?
What is g(x) supposed to represent? I am assuming that what you are calling f(x) is the line through (0, 0) and (4, 3).

I got it! It is the slope of the line = 3/4, so the equation line is 3x/4 ;)
 
Technical point: The equation of the line is y = 3x/4. 3x/4 is not an equation (there's no = .)
 
hehe, "what you can't ignore.." http://bayarearoster.com/js/includes/34/b/happy.gif
 
Mark44 said:
Technical point: The equation of the line is y = 3x/4. 3x/4 is not an equation (there's no = .)

Gooooooooooot it ;)
 
Incognition said:
hehe, "what you can't ignore.." http://bayarearoster.com/js/includes/34/b/happy.gif

Agree ;)
 

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