Find the Center of Mass of a Lamina

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Homework Help Overview

The discussion revolves around finding the x-coordinate of the center of mass of a lamina defined in the first quadrant, bounded by the lines x = 6 and y = 1, with a given density function p(x,y) = x + y + 1.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the setup of integrals for calculating mass and moments, questioning the need for bounding equations. There is uncertainty regarding the correct application of formulas for the center of mass and the moments involved.

Discussion Status

Some participants have identified potential errors in calculations, particularly concerning the moment Myz. There is an ongoing exploration of the correct formulas to use for a two-dimensional object, with some participants suggesting a review of the calculations for clarity.

Contextual Notes

Participants note the simplicity of the boundaries for the region of integration, contrasting it with more complex examples they have encountered. There is also mention of theoretical expectations for the answer, which adds to the discussion's complexity.

jabar616
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Homework Statement



Find the x-coordinate of the center of mass of the lamina that occupies the region cut from the first quadrant by the lines x = 6 and y = 1 if the density function is p(x,y) = x + y + 1

Homework Equations



Mass = ∫∫spdσ
X Coordinate of center of Mass = Myz/M
Myz = ∫∫sxpdσ

The Attempt at a Solution



I am not sure how to set this one up, as I have not seen one like this without a bounding equation (ie x2 + y2 + z2 = a2 or similar.)

I attempted simply setting up the integral as being from 0≤x≤6 and 0≤y≤1 so M=∫∫x+y+1dydx = 27 and Myz = ∫∫x2 +xy +x dydx = 126

However, dividing 126 by 27 results in 14/3, not 11/3 as the answer theoretically should be.

Any help would be greatly appreciated!
 
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The problem appears to be in your calculation of Myz. If you can't find the problem, please post your work here so it can be reviewed in detail.
 
jabar616 said:

Homework Statement



Find the x-coordinate of the center of mass of the lamina that occupies the region cut from the first quadrant by the lines x = 6 and y = 1 if the density function is p(x,y) = x + y + 1

Homework Equations



Mass = ∫∫spdσ
X Coordinate of center of Mass = Myz/M
Myz = ∫∫sxpdσ
Your two formulas above are a bit confusing. You have a two-dimensional object, so the two moments are with respect to the x-axis or the y axis.

The notation Myz is the moment about the y-z plane, which isn't applicable here because the object is two-dimensional.

The formula to use for the x-coordinate is My/M
jabar616 said:

The Attempt at a Solution



I am not sure how to set this one up, as I have not seen one like this without a bounding equation (ie x2 + y2 + z2 = a2 or similar.)
Here the boundaries are a lot simpler: the region is a rectangle, with x ranging between 0 and 6 and y ranging between 0 and 1.
jabar616 said:
I attempted simply setting up the integral as being from 0≤x≤6 and 0≤y≤1 so M=∫∫x+y+1dydx = 27 and Myz = ∫∫x2 +xy +x dydx = 126

However, dividing 126 by 27 results in 14/3, not 11/3 as the answer theoretically should be.

Any help would be greatly appreciated!
 
SteamKing said:
The problem appears to be in your calculation of Myz.
Yes, I agree. BTW, I get 11/3 for the x-coord. at CM.

Please show us your calculations for My.
 
I did end up finding my error, of course it was just a simple issue that I had missed. Thank you all!
 

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