Two negatively charged objects repel each other with a measured force of 6.3 N when they are 0.5 cm apart. If the excess charge on one of the objects is caused by 8.3 x 10^22 extra electrons, use Coulomb's Law to calculate the number of excess electrons on the second object.
The Attempt at a Solution
Since 1e=1.602 x 10^-19C
8.3 X 10^22e = (1.602 x 10^-19 C)(8.3 x 10^22)
=1.3 x 10^4 C
Therefore, 6.3N = (9 x 10^9 N*m^2/C^2)1.3 x 10^4 C)(q2)/(0.005m)^2
=1.3 x 10^-18 C
Since 1C = 6.242 x 10^18e
1.3 x 10^-18C = (1.3 x 10^-18)(6.242 x 10^18)e
I think I might be over complicating this one. Can anybody help me out? Please?