(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Two negatively charged objects repel each other with a measured force of 6.3 N when they are 0.5 cm apart. If the excess charge on one of the objects is caused by 8.3 x 10^22 extra electrons, use Coulomb's Law to calculate the number of excess electrons on the second object.

2. Relevant equations

F=kq1q2/r^2

3. The attempt at a solution

Since 1e=1.602 x 10^-19C

8.3 X 10^22e = (1.602 x 10^-19 C)(8.3 x 10^22)

=1.3 x 10^4 C

Therefore, 6.3N = (9 x 10^9 N*m^2/C^2)1.3 x 10^4 C)(q2)/(0.005m)^2

=1.3 x 10^-18 C

Since 1C = 6.242 x 10^18e

1.3 x 10^-18C = (1.3 x 10^-18)(6.242 x 10^18)e

=8.1e ????

I think I might be over complicating this one. Can anybody help me out? Please?

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# Homework Help: Calculate the number of excess electrons

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