Calculate the position vector for 3di

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To determine if the vectors for 3di are collinear, compare the slopes of the vectors AB, AC, and BC. The slopes of AB and AC have been established as equal. If the slope of vector BC matches these slopes, then the points are collinear. The discussion emphasizes the importance of slope comparison in verifying collinearity. Understanding these relationships is crucial for solving the problem effectively.
homeworkhelpls
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Homework Statement
Calculate the position vector for 3di
Relevant Equations
none
1666203391797.png

for 3di i did the normal AB=BC so b-a would give either satisfy or not this phenomenon, my answer was (3a-1, -4) & (2a^2 + a - 1, 4a - 2), now how would i know from here if they're collinear or not?
 
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homeworkhelpls said:
Homework Statement:: Calculate the position vector for 3di
Relevant Equations:: none

View attachment 315775
for 3di i did the normal AB=BC so b-a would give either satisfy or not this phenomenon, my answer was (3a-1, -4) & (2a^2 + a - 1, 4a - 2), now how would i know from here if they're collinear or not?
I don't know what you mean by "I did the normal AB = AC." The word "normal" usually means perpendicular.
Look at the slopes of the vectors AB, AC, and BC. I've already determined that the slopes of AB and AC are equal. If the slope of vector BC is equal to the other two slopes, then all three points are collinear -- i.e., lie on the same line.
 
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I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks

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