Calculate the translational speed of a cylinder

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Homework Help Overview

The problem involves calculating the translational speed of a cylinder rolling down an incline of 11 meters in height, starting from rest and rolling without slipping. The discussion centers around the conversion of potential energy to kinetic energy, considering both translational and rotational components.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between potential energy at the height of the incline and kinetic energy at the bottom, questioning how to account for both translational and rotational kinetic energy. There are inquiries about the relevant equations and the moment of inertia for a cylinder.

Discussion Status

The discussion is ongoing, with participants sharing equations and expressing uncertainty about their correctness. Some guidance has been provided regarding the relationship between potential energy and kinetic energy, as well as the importance of the moment of inertia. Multiple interpretations of the problem are being explored.

Contextual Notes

Participants note the challenge of deriving the speed from limited information, specifically only having the height of the incline. There are concerns about the accuracy of the equations being referenced and the values being calculated.

Bones
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Homework Statement


Calculate the translational speed of a cylinder when it reaches the foot of an incline 11 m high. Assume it starts from rest and rolls without slipping.


Homework Equations





The Attempt at a Solution


How do you find the speed when you only have the height of the incline?
 
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Bones said:

Homework Statement


Calculate the translational speed of a cylinder when it reaches the foot of an incline 11 m high. Assume it starts from rest and rolls without slipping.

How do you find the speed when you only have the height of the incline?

The height gives you potential energy.

You get KE at the bottom, but be careful you also have rotational KE in the cylinder since it rolled without slipping.
 
I am not sure what the equation is. The only one I found was v=sqrt 10/7gH which was not right.
 
Bones said:
I am not sure what the equation is. The only one I found was v=sqrt 10/7gH which was not right.

Show your equations and perhaps we can see where you are going wrong.
 
There's this one: 1/2Mv^2+1/2Icm(omega)^2+Mgy
But I am not sure where to get all this information from just having the height of the incline.
 
Bones said:
There's this one: 1/2Mv^2+1/2Icm(omega)^2+Mgy
But I am not sure where to get all this information from just having the height of the incline.

Ok. You have your potential energy. And at the bottom what's happened to that PE? It's become KE for this problem. So whjat you have then is

m*g*h = Σ KE = 1/2 m*v2 + 1/2*I*ω2

But what is ω ? Happily ω = v/r

Why happily? Because the moment of inertia also will have a term that relates to r.

Why don't you look up the moment of a cylinder and solve the rest of the problem?
 
The moment of inertial for a cylinder is 2/5Mr^2, but I am still not sure how to solve this. I keep getting 12.4m/s which is not correct.
 

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