Calculate the volume of 1.00 mol of liquid water

[Leo_lee]

Homework Statement

Calculate the volume of 1.00 mol of liquid water at 20°C (at which its density is 998 kg>m3),and compare that with the volume occupied by 1.00 mol of water at the critical point, which
is 56 * 10-6 m3. Water has a molar mass of 18.0 g>mol.

Full answer please!

Thanks,

Homework Equations

1 mole x 18g/mole / .998 g/ml

The Attempt at a Solution

First convert 998 kg>m3 to .998 g/ml

1 mole x 18g/mole / .998 g/ml = ___ml

Then do the same at Tc
But their number looks wrong to me. They're off by a factor >1000

 

[BvU]

hello Leo,

Might first want to study PF guidelines a bit ...

their number

How can I agree or disagree if you don't show it ? (or do you mean the 56E-6 ? That is correct)
Never mind.
Work out your way down to the answer and post your work in detail.

 

[Leo_lee]

the numbers are up there in the problem !

 

[BvU]

So how come you claim a mismatch of > 1000 ?

 

[Leo_lee]

I checked that online : https://en.wikipedia.org/wiki/Supercritical_fluid#Properties

 

[TSny]

But their number looks wrong to me. They're off by a factor >1000

What specific number looks wrong to you?

 

[Leo_lee]

1.00 mol of liquid water at 20°C (at which its density is 998 kg>m3),and 1.00 mol of water at the critical point, which
is 56 * 10-6 m3. Water has a molar mass of 18.0 g>mol.

 

[TSny]

Sorry, but I'm uncertain as to what specific question you are asking.

 

[TSny]

First convert 998 kg>m3 to .998 g/ml

1 mole x 18g/mole / .998 g/ml = ___ml

This looks correct.

Then do the same at Tc
But their number looks wrong to me. They're off by a factor >1000

Here's where I'm not sure what you are referring to.

 

[BvU]

I checked that online : https://en.wikipedia.org/wiki/Supercritical_fluid#Properties

Yes, that's correct, too. Do you know how to convert m3 to cm3 ?

 

[Leo_lee]

I don't !

 

[TSny]

OK, it's a conversion problem.

1 m³ = (1 m) x (1 m) x (1 m). Express each 1 m as so many cm.