Calculate Torque for Pin: L=100.9 cm, M=3.98 kg, m=537 g.

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SUMMARY

The discussion centers on calculating the torque exerted by a pin to prevent a rod from rotating, given specific measurements: length (L=100.9 cm), mass of the rod (M=3.98 kg), and mass of the hanging weight (m=537 g). The relevant equation used is Torque = distance from the pivot * force. The solution involves calculating the torque from both the rod and the hanging mass, treating the rod's mass as concentrated at its center. The total torque is the sum of the individual torques from the rod and the weight.

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Torque of a pin. Please Help!

Homework Statement


How much torque must the pin exert to keep the rod from rotating? (L=100.9 cm, M=3.98 kg, m=537 g.)
I attached the picture of the problem. I am unsure how to approach the problem. I am looking through my College Physics and cannot find an equation to solve this problem. Help please!

Homework Equations


Torque=distance from the pivot*the force


The Attempt at a Solution

 

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PoPrOcKsRoCk said:

Homework Statement


How much torque must the pin exert to keep the rod from rotating? (L=100.9 cm, M=3.98 kg, m=537 g.)
I attached the picture of the problem. I am unsure how to approach the problem. I am looking through my College Physics and cannot find an equation to solve this problem. Help please!

Homework Equations


Torque=distance from the pivot*the force
Okay, so based on that equation how much torque do the bar and hanging mass each exert on the pivot point (pin location)?

You may treat the bar's mass as being located at the bar's center.
 


I got it.

I used the equation T=Fr for the Torque of rod M and the Torque of the weight of m then added both torques.

Thank you.
 

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