Calculated the pressure of the alcohol

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Homework Help Overview

The problem involves determining the pressure inside a bubble of air located 4.0 meters below the surface of liquid ethyl alcohol in a rigid container, where the air pressure above the liquid is given as 1.10 atm. The context is related to fluid mechanics and pressure calculations in liquids.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of pressure at a certain depth in the liquid and question the conversion of density to pressure. There are inquiries about the units used in the calculations.

Discussion Status

Some participants have provided calculations and feedback on the initial attempts. There is a suggestion that the pressure inside the bubble may be assumed to be equal to the pressure of the surrounding liquid, although this assumption has not been universally accepted or confirmed.

Contextual Notes

There is a lack of information regarding the size of the bubble, which may influence the assumptions made about the pressure inside it. Additionally, the problem is framed within the constraints of a homework assignment, which may limit the exploration of alternative approaches.

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Homework Statement


Air is trapped above liquid ethyl alcohol in a rigid container. If the air pressure above the liquid is 1.10atm, determine the pressure inside a bubble 4.0m below the surface of the liquid.

Image: Think of a cylindrical container with a layer of air at the top. The remaining is filled with ethyl alcohol. 4m below the top of the alcohol is a bubble of air.

Homework Equations



P=P(atm)+pgh
p(ethyl-OH)=.806X10^3kg/m^3

The Attempt at a Solution



So i calculated the pressure of the alcohol 4m below the surface and got 1.3X10^5Pa. However, I'm not sure what to do in order to get the pressure in the bubble.
Suggestions would be appreciated.

thanks
 
Last edited:
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How did you go from a density of 0.8X10^3 to a pressure of 1.3X10^5? What units are all these quantities in?
 
This is what i did in order to get the pressure of the ethyl 4m down:

P=1.01310^5Pa+(.806X10^-3kg/m^3)(9.8m/s^s)(4m)=1.33X10^5Pa
 
Looks okay so far.

Now, since they don't tell you the size of the bubble, you are probably expected to assume that the pressure inside the bubble is equal to the pressure of the liquid around it. So you've got the answer you need.
 

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