Calculating AC Current for a 0.197 H Inductor with 166 V Peak Voltage

[kiwikahuna]

Homework Statement

A circuit contains only 0.197 H inductor. An AC voltage of peak value 166 V and frequency 60.5 Hz is applied to the circuit. When the voltage is 166 V, what is AC current? Answer in units of A.

Homework Equations

The Attempt at a Solution

we know that inductive reactance is XL= ωL
AC voltage peak value IS V = 166 Volts
then AC current is I = V/XL
ω = 2π(FREQUENCY) = 2π(60.5) RAD/SEC
L = INDUCTANCE = 0.197 H
THEN I = 166/ 2π(60.5)*0.197 = 2.22 A

The answer is wrong, could someone tell me what I'm doing wrong? Thank you!

 

[Irid]

You have obtained peak AC current, because you used peak voltage in Ohm's law. Probably you're asked to find effective current.

 

[berkeman]

Remember that V = L dI/dt, so there is a phase shift between voltage and current in an inductor. Do you know how many degrees the current waveform is off of the voltage excitation waveform, and in which direction?