Calculating Acceleration and Velocity of a Saturn V Rocket

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The discussion focuses on calculating the acceleration and velocity of a Saturn V rocket with a mass of 2.75 x 106 kg and an engine force of 3.3 x 107 N. The initial vertical acceleration is determined to be 2.2 m/s2 after accounting for gravitational force. The velocity after 8 seconds is calculated to be 17.6 m/s, and it takes approximately 92.9 seconds to reach an altitude of 9500 m using the equations of motion for constant acceleration.

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A Saturn V rocket has a mass of 2.75 x 106 kg and exerts a force of 3.3 x 107 N on the gases it expels. Determine:
a) the initial vertical acceleration of the rocket
b) its velocity after 8 s
c) how long it takes to reach an altitude of 9500 m.
Ignore mass of gas expelled and assume g remains constant


a)Fnet=Fengine-Fgravity
Fengine=Fnet+Fgravity
Fengine=m(a+g)
a=F/m-g=(3.3*10^7 N/2.75*10^6 kg) - 9.8=2.2m/s^2

b) Not sure how to do

c) Not sure how to do

Any help?
 

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Ignore mass of gas expelled and assume g remains constant
That helps, although in reality the mass of the propellant decreases, and at constant thrust the acceleration is continually increasing.

Back the problem at hand.

2. What is the equation for velocity (speed) as a funtion of time when acceleration is constant?

3. What is the equation for distance traveled (altitude gained) for a mass at constant acceleration?

http://hyperphysics.phy-astr.gsu.edu/hbase/mot.html#mot1

This may come in handy later - http://hyperphysics.phy-astr.gsu.edu/hbase/traj.html
 
b) v=v0+at
v=0 + (2.2 m/s^2)(8 s)=17.6 m/s

c)x=v0(t)+1/2at^2
y=v0(t)+1/2at^2
9500=0+.5(2.2)(t^2)
9500/1.1=t^2
t=92.9 s


Better?
 

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