The discussion centers on calculating aerodynamic power (P) required to fly a plane, specifically using the formula P = Mass^(3/2) / √S, where S represents the cross-sectional area of the wing. The values provided are Mass = 124.6 kg and S = √36 m², leading to a calculated power output of approximately 231.5 kg m^-1. The confusion arises from the calculation of 1389, which is derived from rounding the result of (124.6 kg)^(3/2) to 1391, suggesting potential use of logarithmic methods or approximation techniques.
PREREQUISITESAerodynamics students, aerospace engineers, and anyone involved in aircraft design or performance analysis will benefit from this discussion.
negdee said:Homework Statement
aerodynamics question. Power p to fly a plane.
Has p = mass 3/2 do not know if this means square m by 3/2? That is how i take it to be then you divide this by √s which is cross section of wing.
Figures are m = 124.6kg 3/2 divided by s = √ 36m squared
solution comes up with m 1389/s 6m = 231.5kg m to power of -1
i do not know how to get to figure of 1389?