Calculating Air Velocity in a Pipe

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Air flows through a 4" pipe with varying pressure and temperature at two points, A and B. At point A, the pressure is 2 bar and the velocity is 5 m/sec, while at point B, the pressure drops to 1.2 bar with a temperature of 32°C. The specific gravities at both points are calculated, leading to the application of the continuity equation to find the velocity at point B. Initial calculations yield a velocity of 8.6 m/sec, but the expected answer is 7.05 m/sec, prompting a discussion on whether the pressures are gauge pressures. Ultimately, confirming the pressures as gauge pressures resolves the discrepancy.
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Homework Statement


air flows in a 4" pipe. at point A a 2[bar] pressure was measured and the temperature was 22°C. the velocity V1was 5[m/sec].
At point B, down the stream, a 1.2[bar] pressure was measured and the temperature was 32°C.
What is the velocity V2at point B.

Homework Equations


The continuity equation:
\gamma1A1V1=\gamma2A2V2
Where \gamma=specific gravity, A=section area.

The gas law:
pv=RT
Where: p=absolute pressure
v=\frac{1}{\rho}, \rho=specific mass


The Attempt at a Solution


The specific gravity at point A:
\gamma_1=10\frac{2E5}{287\cdot 295}=23.6[N/m^3]

The specific gravity at point B:
\gamma_2=10\frac{1.2E5}{287\cdot 305}=13.7[N/m^3]


The continuity equation, without the area, since it's the same on both points:
23.6\cdot 5=13.7\cdot V_2 \Rightarrow V_2=8.6
The answer should be 7.05.
 
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Are the measured pressures "gauge pressures"?
 
the problem statement is exactly as written in the book.
Maybe they should be, but that's the books mistake.
 
Karol said:
the problem statement is exactly as written in the book.
Maybe they should be, but that's the books mistake.

Well, measurements of pressure are often gauge pressures. See what you get for the answer if you assume they are gauge pressures :smile:
 
yes, thank you, it solved. bye
 
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