The discussion focuses on calculating the angle between two vectors, a = 1.0 ihat + 5.0 jhat + 1.0 khat and b = 6.0 ihat + 3.0 jhat + 4.0 khat, using the scalar product formula a·b = ab cos θ. The scalar product is expressed as a·b = axbx + ayby + azbz, which leads to the equation for θ involving the arccos function and the lengths of the vectors. The solution requires applying Pythagoras' theorem to find the magnitudes of the vectors.
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Write out the expression for [itex]\theta[/itex] in terms of the length of a x length of b and [itex]a_xb_x + a_yb_y + a_zb_z[/itex] (hint: you need the arccos function and pythagoras' theorem).jpd5184 said:Homework Statement
Use the definition of scalar product, a·b = ab cos θ, and the fact that a·b = axbx + ayby + azbz to calculate the angle between the two vectors given by a = 1.0 ihat + 5.0 jhat + 1.0 khat and b = 6.0 ihat + 3.0 jhat + 4.0 khat.
Homework Equations
a·b = ab cos θ
The Attempt at a Solution
i really don't have any clue were to start