Calculating Buoyancy and Weight in a Sinking Ship Diorama

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SUMMARY

This discussion focuses on the physics of buoyancy and weight calculation for a sinking ship diorama. To determine the weight of the toy ship, one must calculate its volume using water displacement, as fresh water weighs 1 kg per liter. The ship must weigh more than the water it displaces to sink, and for every liter of air added from an air compressor, there is a corresponding lift of 1 kg. Additionally, factors such as viscous effects and air bubbles must be considered to achieve accurate sinking behavior.

PREREQUISITES
  • Understanding of Archimedes' principle
  • Knowledge of buoyancy and density concepts
  • Familiarity with water displacement measurement techniques
  • Basic principles of fluid dynamics
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  • Research water displacement methods for accurate volume measurement
  • Explore buoyancy calculations in various fluid densities
  • Learn about the effects of surface area on fluid resistance
  • Investigate the use of air compressors for underwater lifting mechanisms
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Art students, model builders, hobbyists, and anyone interested in the physics of buoyancy and fluid dynamics in diorama construction.

nbontra
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I'm constructing a diorama of a ship sinking, and I haven't been able to find any details on the physics behind it. I'm an art student, so my knowledge in physics is limited to what I read here and in a few books at home.

I'll most likely construct a fish tank that is 4'x1'x1' to contain the water and toy ship. My question is to what formula I would use to determine how heavy to make the toy ship. Is it just a scale issue? Where I could just use the size ratio to figure out the weight? If I go that route, will the amount of water or the size of the tank affect the rate at which it sinks?

Also, I'll be using an air compressor hose to attempt to raise the ship while it is sinking. How does one determine how much air can raise a certain amount of weight underwater?

Thanks!
 
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It depends on the volume and mass of the ship. Unless it is a very simple crude shape it is going to be difficult to calculate the volume of the ship.
To measure the volume fill a container to the top with water, push the model under the water and cathc the extra water that overlfows. The volume of this water is the displacement.
Fresh (ie not salt) water weighs 1Kg / litre so your boat has to weigh more than 1Kg for each litre it displaces.
You will probably have to add weights to make it sink.

Then to make it float again you add air from the hose. For every litre of air you add you get 1kg of lift.

With a detailed model you are also going to have problems with air bubbles caught in small details.
You are probabaly ging to have to experiment to get it right.
 
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Viscous effects, those which influence the resistance of the ship to the water, are related to the surface area of the ship exposed to the water, and determine a terminal velocity for the sinking ship. Buoyancy, or lack of it, determines the acceleration component of sinking, and is related to the density of the ship minus the density of water displaced by it, as mgb_phys mentioned. Take care to consider (or eliminate) any air bubbles, also using Archimedes' principle! A simple shape that you may want to experiment with is that of a submarine rather than a ship.
 
thanks for the info, i surely appreciate it!
 

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