Calculating % Change in Balloon's Volume at Different Altitude and Temp

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To calculate the percentage change in a helium balloon's volume as it rises from sea level to a higher altitude, the ideal gas law (PV=nRT) is applied. The initial and final volumes (V1 and V2) are determined using the pressure and temperature at both altitudes. The percentage change formula, which is (V2-V1)/V1, is confirmed to be unitless since it is a ratio. Concerns about unit consistency in the volume calculation are addressed, emphasizing the need to include n and R in the ideal gas law for accurate unit analysis. Understanding these concepts is crucial for exam preparation.
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Homework Statement



A child holding a helium filled balloon @ sea level (T= 20 C) let's go of the string. The balloon rises freely several thousand meters, where T = 5 C and P = 0.70 atm. Find the percentage change in the balloon's volume.


Homework Equations



PV = nRT

percentage change = amount of change (amt change = V2-V1)/ original amount (V1)

The Attempt at a Solution



Is my reasoning correct on this one? Since n and R don't change with altitude, temperature or volume, I solved for volume: V = P/T Then I solved for V1 and V2. Lastly used the above % change equation.

The only thing that is bothering me about my method is that I'm not sure how the units work out for the volume equation I posted. I guess I am figuring it jut works out (?) But, I really need to understand it for exams :wink: I see no other way to work this problem. Also- is the % change formula correct?

Thanks.
 
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Looks good to me.

Units? Try working them out.
 
V = P/T

m^3 or liters = Pa or (N/m^2) / (C)

I'm still don't understand how it works out. Do you mean work it out with the n and R included?
 
When you are calculating percent change in volume, that is a ratio and there are no units; they cancel out.

However, when working out the units in the ideal gas law, you will need to include nR, (or Nk):

PV=NkT=nRT
 
Thank you BF.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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