Calculating charge dissipation given two hanging masses

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SUMMARY

The discussion focuses on calculating the rate of charge dissipation for two hanging masses with identical charges forming an angle theta from the vertical. The key equation presented is dq/dt = dx/dt * dq/dx, where dq/dt represents the rate of charge loss, dx/dt is the given instantaneous velocity, and dq/dx is the change in charge concerning the distance from the vertical. The solution involves recognizing that the charges trace a circular path, leading to the conclusion that the velocity should be expressed as L*d(theta)/dt, where L is the string length. The final recommendation is to derive the equation for theta with respect to time to isolate dq/dt.

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Homework Statement



Two hanging masses have an identical charge and create an angle theta from the vertical. If they start losing their charge and have an instantaneous velocity of XX m/s(given), find the rate in which they are losing the charge.

Homework Equations



Coulumbs Law

The Attempt at a Solution



The first part of the question was to find theta, which I did. I now have no idea how to handle it from here. The only thing I came up with is-

dq/dt = dx/dt * dq/dx

Where dq/dt is what I am trying to find, dx/dt is the given velocity and dq/dx would be the change in charge in terms of the distance from the vertical. I'm not sure how to find that.

Thanks.
 
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I don't think dx/dt is the instantaneous velocity, because the velocity should also include dy/dt. Instead, the charges are tracing out a circle, so their velocity should be L*d(theta)/dt, where L is the length of the string.

Since you already have an equation for theta, presumably in terms of q, why not derive both sides with respect to time? On the left side, you'll get d(theta)/dt. On the right side, you'll get a factor of dq/dt, which is the factor you're trying to solve for.
 

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