Calculating Charge Needed for Same Binding Energy in H2+

[ghallya]

hi I need help in solving this

The protons the H2+ molculer ion are 0.106 nm apart and the binding energy of H2+ is 2.65 ev , what negetive charge must be placed halfway between two protons this distance apart to give the same binding energy?

I calculated it for the electrons , but here i didn know for the protons ?
I tryed to use the graph I had but I don't think its the right solution
so if someone could help me or give an equation I could apply

thanx

 

[maverick280857]

Please correct me if I'm wrong...

The two protons repel each other so left to itself, the two proton system is electrostatically unstable. You need a negative charge somewhere between them so that they are both attracted to the -ve charge and effectively stay in place. The binding energy is now defined in terms of the 3 charge system: 2 protons + 1 negative charge. [No other nuclear force is being considered for the mathematical calculations]

Does this help?

PS--Show your work