Calculating Choked Flow of Propane Through a Valve

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Discussion Overview

The discussion revolves around calculating the choked flow of propane through a valve based on the choked flow of natural gas. Participants explore the implications of relative densities of the gases involved and the appropriate equations to use for the calculation.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant questions the necessity of the relative density of natural gas in the calculation.
  • Another participant proposes using the equation Qvf = Qvr * sqrt(1/d) to find the choked flow of propane, substituting the values for natural gas and propane.
  • A different participant calculates Qvf using the relative density of natural gas and arrives at a different answer, suggesting multiple possible outcomes based on the interpretation of the problem.
  • There is a discussion about whether to use the relative density of the reference gas (0.65) or the actual gas (1.45) in the calculations.
  • Some participants express uncertainty about the correct application of the formula and seek clarification on the terms involved.
  • One participant suggests an alternative formula involving the densities of the gases, leading to a different calculation for Qvf.
  • There is a request for confirmation on the calculations and the stability of the system in a separate but related question about control systems.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the correct approach to calculate the choked flow, with multiple competing views and interpretations of the problem remaining unresolved.

Contextual Notes

Participants express confusion regarding the relevance of relative densities and the correct application of the formula, indicating a lack of clarity in the problem statement. There are also unresolved mathematical steps and assumptions about the reference gas.

Who May Find This Useful

Students working on fluid dynamics or gas flow calculations, particularly in the context of homework or coursework related to engineering or physics.

cps.13
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Hi,

Homework Statement


I have the following question in my course work. What I do not understand is why it provides the relative density of natural gas?!

Calculate the equivalent choked flow of propane through a particular valve if the choked flow of natural gas through it is 10 litres s–1.

The relative density* of propane is 1.45 and that natural gas is 0.65. [*with reference to air]

Homework Equations


I believe the equation I need to use is:

Qvf = Qvr * sqrt(1/d)

Where

Qvf = volumetric flow of the actual fluid (the propane)
Qvr = volumetric flow of the reference fluid (the natural gas) = 10l/s-1
d = relative density of the actual fluid = 1.45

The Attempt at a Solution


So

Qvf = 10 * sqrt (1/1.45) = 8.304L/s-1

Am I going wrong somewhere?

Thanks
 
cps.13 said:
Hi,

Homework Statement


I have the following question in my course work. What I do not understand is why it provides the relative density of natural gas?!

Calculate the equivalent choked flow of propane through a particular valve if the choked flow of natural gas through it is 10 litres s–1.

The relative density* of propane is 1.45 and that natural gas is 0.65. [*with reference to air]

Homework Equations


I believe the equation I need to use is:

Qvf = Qvr * sqrt(1/d)

Where

Qvf = volumetric flow of the actual fluid (the propane)
Qvr = volumetric flow of the reference fluid (the natural gas) = 10l/s-1
d = relative density of the actual fluid = 1.45

The Attempt at a Solution


So

Qvf = 10 * sqrt (1/1.45) = 8.304L/s-1

Am I going wrong somewhere?

Thanks

Hi CPS.13

As I have the same question as you got .
I used the same solution as you posted on here but I don't understand when it said "that natural gas is 0.65 [with reference to air] "
does the question ask to find both of density of propane and natural gas ?

QVF = 10 x sqrt (1/0,65) = 12.4 l/s-1

So this question will have 2 answers . This is what I understand .
 
jaff90110 said:
Hi CPS.13QVF = 10 x sqrt (1/0,65) = 12.4 l/s-1

The relative density of the reference gas is 0.65. The relative density of the actual gas is 1.45.
 
cjm181 said:
The relative density of the reference gas is 0.65. The relative density of the actual gas is 1.45.
Thank you cjm181for reply this thread agai,
So we only need to find the equivalent choked flow by using the relative density of the reference gas which is 0.65 . There is nothing to do with the actual gas ? From equation qvf = qvr x sqrt 1/ 0.65 is that right ?
 
Nearly. Find the full formula for qvf. What are the terms?

Specifically the 1. what term is there?
 
cjm181 said:
Nearly. Find the full formula for qvf. What are the terms?

Specifically the 1. what term is there?

The full formula is qvf =qvr x √ρR/ρF
 
yes, so what reference gas are we using? is it 1 or 0.65
 
cjm181 said:
yes, so what reference gas are we using? is it 1 or 0.65

For reference gas, using 0.65 .
then
qvf = 10 x √0.65/1.45
= 6.7 L s^-1
is that correct?
 
  • #10
That's what i got!
 
  • #11
cjm181 said:
That's what i got!

So that is final formula that we need to use with that answer right?
But why we could not apply for the qvf = qvr x √1/d ?
 
  • #12
Could you please help me with this question again?

1. Write down expression for the open-loop , loop , closed loop gains of the system shown in below , in term of the stage gains A,B,C .
Here is my work .

a)
Open Loop gain = A x B

Loop gain = A x B x C

Closed Loop gain = θo/θi = A x B x C / (1+(A x B) x C)b) The table below gives the magnitude and phase angle of the stage gains of the system represented by block diagram shown in below . Magnitude of gain Phase angle
Controller A 0.5 13°
Process B 2 113°
Measuring System C 0.5 47°- Determine if the system is stable ?
here is my work ,
Loop gain = A x B x C
= 0.5 x 2 x 0.5
= 0.5
As the loop gain of a system is less than unity , this is stable system.

- Determine the new value of controller gain that will cause the system output oscillate with constant amplitude.

Controller gain x 2 x 0.5 = 1

Controller gain = 1/2 x 0.5 = 1

Could you please check this out for me , as I'm not confidence these are the right answer. Thank you
 

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