Calculating combined resistance of wires

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Homework Statement



upload_2015-5-22_8-19-31.png

Homework Equations


  • R ∝ 1/A

The Attempt at a Solution


Since there are six copper wires and a steel core, I added the resistance of all the wires and the core and divided them by 7, though I don't think my approach is right since the resistance of the copper and steel wires are different. As such my answer is about 22.9Ω, which is wrong. The answer is B, 1.6Ω, which is just the quotient of the the total resistance of the six copper wires. Why is the resistance of steel core not taken into account in this case?
 

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Ermm...yes. But why is the steel not taken into account?
 
Oh, so is the working 6(1/10) + 1/100 correct for 1/R?
 
Thanks. So is this combined resistance of six different copper wires and steel less than a power cable just made up of one copper wire of the same cross-sectional area?
 
I think the resistance of six different copper wires and the steel would be lesser. However if it's just the six copper wires without the steel, then they would be the same.
 
Why quite so? Is it not really correct?:smile:
 
Since resistance values are given we need think about type of wire.
From situation they are in parallel connection.
Please see the attachment
 

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