Calculating Distance and Speed: Solving a Robert Service Question

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Homework Help Overview

The problem involves calculating the distance covered by Robert Service while racing down the Mackenzie river, factoring in changes in speed due to the loss of two dogs from his sled team. The scenario presents a complex relationship between distance, speed, and time, with specific conditions affecting the overall outcome.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss various equations and relationships between distance, speed, and time, with some attempting to derive equations based on the information provided. There are questions about how to effectively use the last piece of information regarding the two dogs and its impact on the overall timing.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem. Some have proposed equations and calculations, while others suggest the need for additional equations to solve for the unknowns. There is no explicit consensus on the approach or solution yet.

Contextual Notes

Participants note that the problem involves multiple unknowns and that the information given may lead to different interpretations. There are constraints related to the assumptions made about speed and time, particularly regarding the impact of the two dogs on the overall journey.

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Homework Statement


Robert Service race down the frozen Mackenzie river to rendezvous with Sam McGee who lay dying in a camp. He had a team of five huskies pulling his sled at full speed for 24 hours, then 2 dogs ran off. The trip continued at 3/5 the original speed
and he reached his goal 48 hours later than he would have had the full speed been maintained. If the the two fickle dogs had stayed on the job for an additional 50km, he would arrive 24 hours late instead. What distance did the trip cover?

Homework Equations


d= vt


The Attempt at a Solution


I believed the first equation was
d = (v x 24) + (3/5v x 48) and d+50 = v x 24, isolated the two d and solved for the original speed, however my teacher told me I was way off. I am not quite sure of how to approach this question, and any help would be greatly appreciated.
 
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The key seems to be the last bit of information. If the 2 dogs had stayed for 50 more km then he would have been 24 hours late, not 48. So those 2 dogs contributed a difference of 24 hours. How can you use that?
 
Yes. Your equation has two unknowns, d and v. To solve for v, you need to know d and to get that you need to use the last bit of information, that you did not use, to get a second equation.
 
I got the same question,
so in the final part he would travel 50km in 24 hours
and he would have also traveled 50km in 24 hours with 3 dogs
and in the first 24 hours it would be 50/3 x 5 = 83.3333
so total distance would equal 50 + 50 + 83.333 = 183.333km?
cheya richezzzyy
 
Actually, I set a system of five equations with five unknowns. The unknowns are distance traveled, speed with five dogs, remaining time employed (i.e. apart from the 24 hours) had the full speed been maintained, remaining time employed with three dogs in the first situation, and remaining time employed with three dogs in the latter case. The answer is not 183.333 km.
 
I have the possible answers for this question from my teacher:100, 133, 167, 200, or 267 (all kilometers)
 
Good question this, you need to write everything clearly and continue even when it looks impossible. Calculate everything you can and you'll get there.
 

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