Calculating Electric Field at a Point from Multiple Charges

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SUMMARY

This discussion focuses on calculating the electric field at a point in space due to multiple point charges using the superposition principle. The charges involved are q1 = q located at (1,2,3) and q2 = 2q at (4,5,6). Participants clarify the need for unit vectors in the calculations and emphasize the importance of correctly applying the formula E = 1/[4*Pi*epsilon0] * (q/r1^2 * r1/|r1| + q/r2^2 * r2/|r2|). The conversation also touches on integrating electric fields from linear charge distributions along the axes.

PREREQUISITES
  • Understanding of electric field calculations from point charges
  • Familiarity with vector mathematics and unit vectors
  • Knowledge of the superposition principle in electrostatics
  • Basic calculus for integrating electric fields from continuous charge distributions
NEXT STEPS
  • Study the derivation and application of the electric field formula E = k * q / r^2
  • Learn about unit vector calculations in three-dimensional space
  • Explore the integration of electric fields from continuous charge distributions
  • Investigate the implications of charge density variations on electric field calculations
USEFUL FOR

Students and professionals in physics, electrical engineering, and anyone involved in electrostatics or electric field calculations.

  • #31
You should be using z^2 + x^2... L should only be in the limits of your integral...

Is E_z the only answer given in the back?
 
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  • #32
yes the only answer, this is what needed i guess.

Why do you ask? is it wrong?
 
  • #33
yevi said:
yes the only answer, this is what needed i guess.

Why do you ask? is it wrong?

No, well that's the z-component... that doesn't include the other component... maybe I misunderstood the problem somehow... or maybe they left out that component... not sure...

Did they ask for the total field at (0,0,z), or just the z-component of the field at (0,0,z) ?
 
  • #34
Sorry, just the Z.

Thanks, I got it :) .
 
  • #35
yevi said:
Sorry, just the Z.

Thanks, I got it :) .

Ah. cool. :smile:
 

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