Calculating Electric Field at Origin for Rotated Square of Positive Charges

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SUMMARY

The electric field at the origin due to three positive charges +Q located at the corners of a square rotated 45 degrees with respect to the x-axis can be calculated using vector analysis. The charges are positioned at (-a, 0), (a, 0), and (0, -a). The contributions from the charges at (-a, 0) and (a, 0) cancel each other out, leaving only the charge at (0, -a) to influence the electric field at the origin. The resulting electric field can be expressed in terms of the variables Q and a, specifically focusing on the vertical component from the charge at (0, -a).

PREREQUISITES
  • Understanding of electric fields and forces
  • Familiarity with vector addition and cancellation
  • Knowledge of basic electrostatics principles
  • Ability to apply trigonometric functions in physics problems
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  • Study the principles of electric fields generated by point charges
  • Learn about vector components and their role in electric field calculations
  • Explore the concept of electric potential energy in electrostatics
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1. Three posative charges +Q lie on the corners of a square which is rotated 45 degrees with respect to the x-axis. Calculate the electric field at the origin, in terms of the variables Q and a.

I think this question is much easier than I think it is but I'm stuck on it. There is a picture along with this problem but it isn't very complex so i'll describe it here. As stated in the problem the square is rotated 45 degrees with respect to the x axis. Then the 3 charges +Q are located at 3 corners located at: (-a, 0), (a, 0) and (0, -a). I'm assuming this is an Electric Potential Energy problem because it comes in that section of the homework (however, this may not be the case).

So far I've got out of my notes that V = -Edcos(ø). Solving for E gives: E = -(V/dcos(ø))

I've also noticed that the charges at (-a, 0) and (a, 0) will cancel each other out leaving only (0, -a) affecting the force on the origin. I know that I could also substitute EPE/q for V, but I don't think this is the route to go.
 
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