# Calculating Electric Field due to a Dipole

## Homework Statement

Two dipoles are oriented as shown in the diagram below. Each dipole consists of two charges +q and -q, held apart by a rod of length s, and the center of each dipole is a distance d from location A. If q = 4 nC, s = 1 mm, and d = 6 cm, what is the electric field at location A?

As I am unaware of how to attach a file, here is a diagram
************+
************-
************|
************|
************|
************|
-***********|
+--------------A

the *s are there for formatting, or the else lines do not align

## Homework Equations

(1/4*pi*epsilon)*(2qs/d^3) is the electric field of a dipole, on the dipole axis
and
(1/4*pi*epsilon)*(qs/d^3) is the electric field of a dipole, perpendicular to the dipole axis

## The Attempt at a Solution

Plugging the values given, I used the latter equation for the x component, and by doing (9e9)(4e-9*1e-3)/(6e-2)^3 I obtained 166 N/C.

I used the first equation for the y component and obtained 333 N/C

I know there is no z component, so I input <166, 333, 0> N/C, yet this is wrong. Can somebody explain to me what I am doing? I attempted submitting -166 for the x component in case I had somehow misinterpreted the direction of the field, but that was also wrong. Does anybody understand what I am doing wrong?

Last edited: