Calculating electric field due to charge distribution

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SUMMARY

The discussion focuses on calculating the electric field due to a charge distribution using the equation E = kq/r², where λ = dq/dx and Q = λa. A participant seeks clarification on the distance used in the solution, specifically the term (a+r-x), which represents the distance from a segment at position x to the charge distribution. The consensus is that the distance should be interpreted as the distance from the right end of the rod to a point P located to the right of the rod, rather than involving the charge q directly.

PREREQUISITES
  • Understanding of electric field concepts and equations, specifically E = kq/r².
  • Familiarity with charge distribution and linear charge density (λ = dq/dx).
  • Knowledge of integration techniques for calculating electric fields from continuous charge distributions.
  • Basic understanding of coordinate systems in physics, particularly in relation to charge placement.
NEXT STEPS
  • Study the derivation of electric fields from continuous charge distributions using integration techniques.
  • Learn about the concept of linear charge density and its applications in electric field calculations.
  • Explore the implications of distance in electric field equations, particularly in varying coordinate systems.
  • Review examples of electric field calculations for different charge configurations, such as rods and disks.
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Physics students, educators, and anyone involved in electrostatics who seeks to deepen their understanding of electric fields due to charge distributions.

henry3369
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Homework Statement


http://imgur.com/EiCFIDe

Homework Equations


E = kq/r2
λ = dq/dx
Q = λa

The Attempt at a Solution


Here is the book solution:
http://imgur.com/aKSeKo0

I need help with part (a). I understand everything in the solution except for the distance they used for between (r2 in the equation above). It seems they used (a+r-x) and they say that is the distance between a segment at x and the charge q. What does q have to do with the problem at all? Part (a) asks for the electric field due to the charge distribution Q where x > a. So shouldn't the distance be between dx(a segment on the charge distribution) and x?
 
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You are right, it should not have mentioned q in the solution for (a). But the derivation is OK if you think of r as the distance from the right end of the rod to some arbitrary point P located to the right of the rod.
 

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