Calculating electric field given velocity and magnetic field

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SUMMARY

The discussion focuses on calculating the electric field (E) for an electron moving at a velocity (v) of 93 m/s in the presence of a magnetic field (B) of 4.00 T. The formula used is v = E/B, which led to an initial incorrect assumption of E being 372 N/C. The correct value is -372 N/C, determined by applying the right-hand rule to ensure the electric force opposes the magnetic force acting in the +y direction.

PREREQUISITES
  • Understanding of electric fields and magnetic fields
  • Familiarity with the right-hand rule for determining force directions
  • Knowledge of vector notation in physics
  • Proficiency in using the formula v = E/B
NEXT STEPS
  • Study the right-hand rule in detail to understand force directionality
  • Learn about Lorentz force and its implications in electromagnetic fields
  • Explore vector notation and its applications in physics problems
  • Investigate the relationship between electric and magnetic fields in different scenarios
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Physics students, educators, and anyone studying electromagnetism or preparing for exams involving electric and magnetic field calculations.

RKOwens4
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Homework Statement



In the figure below, an electron moves at speed v = 93 m/s along an x-axis through uniform electric and magnetic fields. The magnetic field B is directed into the page and has magnitude 4.00 T. In unit vector notation, what is the electric field?

Figure: http://imageshack.us/photo/my-images/233/webassign2.jpg/

Homework Equations



v=E/B

The Attempt at a Solution



I know that the answer is 0 for the i and k direction. I thought for the j direction, I just had to use the formula v=E/B, which would give me 372. But that's incorrect. I don't know what else to try.
 
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Have you tried -372 ?
 
That did it! Thanks.
 
RKOwens4 said:
That did it! Thanks.

Good. Usually when they don't specify a direction for the z-axis, you will need to try both + and - signs.
 
Note that getting the sign right isn't a matter of guessing. From the right-hand rule, you should be able to see that the magnetic force will point in the +y direction. To cancel it, the electric force must point in the -y direction.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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