Two point charges of magnitude +q and -q are placed on x-axis separated by distance d, as shown in the figure I provided (You can also look at the website I created). The point P together with the points where the two charges are placed forms an equilateral triangle. What are the direction and strength of the electric field at the point P? Let the constant of proportionality in Coulomb's Law be k.(adsbygoogle = window.adsbygoogle || []).push({});

My idea:

a.) For the direction, we can see that if use to calculate the electic field, point P will be positive and in that case, the Resultant force for y-axis will be zero because it cancels out. So the x-axis will rule in this point so it will probably points in the direction D. Am i correct?

b.)Also calculating the electric field using point P as positive charge, it will also cancel out and the resulting magnitude will be (From equation: E=F/q) E= 2kq/d. Am I also correct?

This is the website: www.geocities.com/willydavidjr/electricfield.html

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# Homework Help: Calculating Electric Field Magnitude and Direction

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