Calculating Electric Field of a Square Wire

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SUMMARY

The discussion focuses on calculating the electric field generated by a square wire configuration. The user successfully computes the electric field from the sides of the square that are perpendicular to the x-axis but struggles with the sides parallel to the x-axis. Key equations mentioned include the electric field formula E = (k)q/r², where k is Coulomb's constant, and the need for integration involving three variables: k, r, and a differential charge element dQ. The suggestion to position the square wire in the x-y plane is noted as a potential simplification for the calculations.

PREREQUISITES
  • Understanding of electric fields and Coulomb's law
  • Basic knowledge of calculus, particularly integration
  • Familiarity with differential charge elements in electrostatics
  • Concept of coordinate systems in physics
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  • Learn about the application of coordinate transformations in electrostatics
  • Explore the use of symmetry in simplifying electric field calculations
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Physics students, electrical engineers, and anyone interested in electrostatics and electric field calculations will benefit from this discussion.

anap40
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I need to calculate the electric field caused by a square of wire.

I can get the field caused by the sides of the square that are perpendicular to the x-axis but I can't figure out how to get the field caused by the side parrallel to the x axis.

here is an image of the problem.
http://img152.imageshack.us/my.php?image=46151722si8.png

At the origin there is no force in the x direction but in other places there is.

I know the the electric field = (k)q/r^2 but when I try to integrate I think I will need 3 variables.

I'd appreciate any help.
 
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Uh are you sure you are not suppose to find the electric field at a given point? Also maybe placing the square wire in the x-y plane will make it simpler. Regarding needing three variables k is constant, r varies (a function of a variable ex. X), and you take a small element of charge dQ (which should have dx or whatever you choose).
 

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