Calculating Electric Flux Through a Cube

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SUMMARY

The electric flux through a cube with a point charge of 9.10 nC at its center can be calculated using Gauss's Law, which states that the total electric flux Φ through a closed surface is equal to the enclosed charge Q divided by the permittivity of free space ε₀. For a cube, the total flux is given by Φ = Q/ε₀, and due to symmetry, the flux through each of the six faces is equal, resulting in Φ_face = Φ/6. For a cube with sides of length 0.250 m, the same principle applies, and the flux can be determined using the same total flux value.

PREREQUISITES
  • Understanding of Gauss's Law
  • Knowledge of electric flux and its calculation
  • Familiarity with the concept of symmetry in electric fields
  • Basic principles of electrostatics
NEXT STEPS
  • Study the derivation of Gauss's Law in electrostatics
  • Learn about the permittivity of free space (ε₀) and its significance
  • Explore examples of electric flux through different geometries
  • Investigate the application of symmetry in electric field problems
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone preparing for exams involving electric fields and flux calculations.

stylez03
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Electric Flux of a cube

Homework Statement


A point charge of magnitude 9.10 nC is at the center of a cube with sides of length 0.685 m.

What is the electric flux through each of the six faces of the cube?

What would be the flux Phi_1 through a face of the cube if its sides were of length 0.250 m?

Homework Equations


4*pi*Q


The Attempt at a Solution



I tried 4*pi*9.10 which equals 411 and it says I'm off by an additive constant

I know to do part2, the flux must be found for part1 but I'm not sure if I'm applying gauss's law correctly, I know that you can use symmetry to solve these cube problems but I haven't had a decent example of this type of problem and we already have homework on it.
 
Last edited:
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Hint: What's the total flux through any closed surface that surrounds a charge Q? Once you find the total flux, then use symmetry to find the flux through each side of the cube.
 
Doc Al said:
Hint: What's the total flux through any closed surface that surrounds a charge Q? Once you find the total flux, then use symmetry to find the flux through each side of the cube.

Is the flux on any surface that surrounds a charge Q => Qenclosed / Eo
 
Last edited:
stylez03 said:
Is the flux on any surface that surrounds a charge Q => Qenclosed / Eo
Yes it is.
 
Doc Al said:
Yes it is.

Though with this, knowledge, I'm still not sure how to figure out the flux on each side of the cube.
 
Start by figuring out which side has the most flux passing through it. :wink:
 
hummm is it Q/Eo/6?
 

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