Calculating Electron Count and Net Charge in Water

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Homework Help Overview

The discussion revolves around calculating the number of electrons and the net charge in a liter of water, focusing on the properties of water and its molecular structure.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between the mass of water, the number of moles, and the number of molecules to determine the total electron count. Questions about the density of water and its implications for calculations are raised.

Discussion Status

Some participants have provided hints and guidance on how to approach the problem, while others have shared their calculations and results. There is a sense of collaboration, with some seeking confirmation of their findings.

Contextual Notes

Participants are working within the constraints of a homework assignment, which may limit the information they can use or the methods they can apply.

WGDawg3
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First post here, so I wanted to say hello first of all. Must admit this board seems quite helpful. Anyways, here's my problem I'm having issues with, any help would be great.

Water has a mass per mole of 18.0 g/mol, and each water molecule (H2O) has 10 electrons. (a) How many electrons are there in one liter (1.00x10^-3) of water? (b) What is the net charge of all these electrons?

I'm not even sure where to get started which is my main problem. Thanks again.
 
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Hint: What's the density of water?
 
A mole of water contains Avogadro's number of molecules, 6.02*10^23 and it has a mass of 18g. A liter of water has a mass of 1000g. So how many moles in one liter? Hence how many molecules in one liter? Hence how many electrons in one liter? Etc. Does that get you started?
 
Dick said:
A mole of water contains Avogadro's number of molecules, 6.02*10^23 and it has a mass of 18g. A liter of water has a mass of 1000g. So how many moles in one liter? Hence how many molecules in one liter? Hence how many electrons in one liter? Etc. Does that get you started?

I think I can maybe go with that... It's been a while since I've done anything physics related so I'm extremely rusty. Thanks, I'll be back quick with a response.
 
OK, I took that info and did my best to work out the problem... I came up with 3.34x10^26 which was very close to one of the answer choices provided by my professor. Anyone mind double checking me?

The other 4 choices were:

4.25x10^25
1.62x10^26
1.08x10^25
5.05x10^26
 
That looks fine to me.
 
Awesome, thanks a ton!
 

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