Calculating Electron Flow in a Copper Wire

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An electric current of 6 A flows through a 5 mm diameter copper wire that is 10 m long. The calculation for the average number of electrons flowing through a cross-section of the wire per second involves using the relationship I=Q/t. The result is approximately 3.744E19 electrons per second. The diameter and length of the wire were found to be unnecessary for this specific calculation. The discussion concludes with a resolution of the problem, affirming the correctness of the solution.
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Homework Statement



An electric current of 6 A flows through a 5 mm diameter copper wire with a length of 10 m.
What is the average number of electrons that flow through a cross section of the wire per second?

Homework Equations



I=Q/t or I=dQ/dt Maybe, I am not sure

The Attempt at a Solution


1 Coulomb = 6.24e18
6*6.24e18
3.744E19 e/s
 
Last edited:
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nvm i figured it out thanks anyway!
 
Weird as the diameter and length are unnecessary. But thumbs up for solving it!
 
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