Calculating EMF and Current in a Circuit with Internal Resistance

[Gunner1412]

Homework Statement

A 5.60ohm resistor is connected to a battery that has 0.200ohm internal resistance, and a terminal voltage of the battery is 10.0V. What is the current in the resistor? What is the emf of the battery?

Homework Equations

EMF=terminal voltage+(I)(Rint.)
V=RI

The Attempt at a Solution

E-I₁Ri-I₁R₁=0
10=5.8I
I=1.72.
EMF=10+0.344=10.34

Help guys? Exam tomorrow at nine and this is the last problem I don't understand! Very much appreciated :)

 

[Doc Al]

The Attempt at a Solution

E-I₁Ri-I₁R₁=0
10=5.8I
I=1.72.
EMF=10+0.344=10.34

Looks good. (But is the resistor 5.6 or 5.8 ohms?)

 

[Gunner1412]

5.6+0.2 for R1+ri... no?

 

[rl.bhat]

E-I1Ri-I1R1=0
10=5.8I
I=1.72.
EMF=10+0.344=10.34
The terminal voltage is the voltage across the resistance. So V = IR1.= ER1/(R1 + Ri ).

 

[Doc Al]

5.6+0.2 for R1+ri... no?

No, 10V is the terminal voltage, which equals EMF - Iri. Thus 10 = I*5.6. (From your equation: E-I1Ri-I1R1=0.)