Calculating Energy for Orbital Deployment

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SUMMARY

The discussion focuses on calculating the energy required to deploy a 100kg experimental package into orbit at an altitude of 1,000 km above Earth's surface. The key equations involved are the gravitational potential energy equation (Ep = -Gm1m2/r) and the work equation (w = fd). The initial calculations for the work done to lift the package are based on the gravitational force, but the participants highlight the need to account for the variable nature of gravity at different altitudes. The correct approach involves using the concept of gravitational potential energy to determine the work done against gravity.

PREREQUISITES
  • Understanding of gravitational potential energy (Ep = -Gm1m2/r)
  • Knowledge of work and force equations (w = fd)
  • Familiarity with the concept of variable gravitational force
  • Basic physics principles related to orbital mechanics
NEXT STEPS
  • Calculate the gravitational potential energy at 1,000 km using Ep = -Gm1m2/r
  • Learn about the concept of variable gravitational force and its implications for work done
  • Explore the calculations for circular orbital velocity and energy requirements
  • Investigate the differences between launching a payload and maintaining it in orbit
USEFUL FOR

Students studying physics, aerospace engineers, and anyone interested in orbital mechanics and energy calculations for satellite deployment.

ashvuck101
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Homework Statement



A scientist wants to put an 100kg experimental package in orbit around the Earth. The cost of deployment depends on the amount of extra energy it takes to get it into the required position i.e. how much more energy is used than just sending the rocket up there.

a) Determine the amount of work that must be done to get the package to 1 000km above the Earth’s surface.

b) Determine the amount of extra work needed to put the package into a circular orbit at this height.


Homework Equations



Ep=-Gm1m2/r

w=fd

f=Gm1m2/r2

The Attempt at a Solution



using

f=Gm1m2/r2

= 9.83*102

w=fd
= 9.83*102*100000
= 9.83*107


b)

im not sure if a is right and i don't know how to get the answer for b

somebody at least tell me i am going in the right direction here
 
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Hi ashvuck101,

ashvuck101 said:

Homework Statement



A scientist wants to put an 100kg experimental package in orbit around the Earth. The cost of deployment depends on the amount of extra energy it takes to get it into the required position i.e. how much more energy is used than just sending the rocket up there.

a) Determine the amount of work that must be done to get the package to 1 000km above the Earth’s surface.

b) Determine the amount of extra work needed to put the package into a circular orbit at this height.


Homework Equations



Ep=-Gm1m2/r

w=fd

f=Gm1m2/r2

The Attempt at a Solution



using

f=Gm1m2/r2

= 9.83*102

Okay, this is the force of gravity on the object at the Earth's surface.

w=fd
= 9.83*102*100000

You seem to be missing a zero here for the distance.

But more importantly, this approach is what you would use if the gravitational force were constant over the entire 1000 km. (Because to find the minimum energy, you would set the pushing force to be equal to the gravitational force.) However, gravity decreases with height. How do you find the work of a force that is not constant?

As an alternative, what is the definition of potential energy? How can that help you find the work done by gravity?


= 9.83*107


b)

im not sure if a is right and i don't know how to get the answer for b

somebody at least tell me i am going in the right direction here
 

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