Calculating Euler Buckling of Open I Beam in 3 Point Bending

Click For Summary
To calculate Euler buckling for an open I beam under three-point bending, the Euler equation Pcr=(π²EI/L) is applicable for columns with pinned ends but requires adaptation for beams. The discussion emphasizes the need to consider both bending and axial compressive stresses in the design, governed by relevant Steel Codes. The formula f_a/F_a + f_b/F_b ≤ 1.0 is suggested to ensure that the actual stresses do not exceed allowable limits. Actual design axial compressive stress (f_a) and bending stress (f_b) must be evaluated against their respective allowable stresses (F_a and F_b). Understanding these relationships is crucial for accurate buckling analysis in beam-column scenarios.
THE 1
Messages
20
Reaction score
0

Homework Statement



I want to find the euler buckling for a open I beam( middle section like a box) that is subjected to three point bending with a point load on top.
I am not so interest in a solution but explanation on how this could be worked out using the euler equation for buckling.



Homework Equations


Pcr=(PI^2)EI/L I am pretty sure this is for a column with pinned ends but don't know how to work out one for an i beam in 3 point bending


The Attempt at a Solution


Don't want a solution can put numbers in myself
 
Physics news on Phys.org
THE 1 said:

Homework Statement



I want to find the euler buckling for a open I beam( middle section like a box) that is subjected to three point bending with a point load on top.
I am not so interest in a solution but explanation on how this could be worked out using the euler equation for buckling.



Homework Equations


Pcr=(PI^2)EI/L I am pretty sure this is for a column with pinned ends but don't know how to work out one for an i beam in 3 point bending


The Attempt at a Solution


Don't want a solution can put numbers in myself
If you are talking about an I beam subject to both bending stresses and axial compressive stresses, then the beam-column design would be governed by the applicable Steel Code. Now mind you I haven't kept up with the latest Code revisions, but generally speaking, especially when the actual axial stress is small compared to the allowable axial stress, stresses would have to satisfy the following formula:
f_a/F_a + f_b/F_b <= 1.0 , where
f_a = actual design axial compressive stress
F_a = Allowable axial compressive stress as if there were no bending (this is generally the Euler buckling stress pi^2EI/KL^2(A) for K=1, with appropriate safety factors)
f_b = actual design compressive bending stress
F_b = Allowable compressive bending stress as if there were no axial load (this allowable stress must take into account lateral torsional buckling of the flange due to the compressive bending stresses, with appropriate safety factors).
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 15 ·
Replies
15
Views
4K
  • · Replies 24 ·
Replies
24
Views
5K
Replies
3
Views
2K
Replies
5
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 4 ·
Replies
4
Views
5K
Replies
6
Views
2K
Replies
1
Views
2K
Replies
5
Views
4K