Calculating Final Velocity After Inelastic Collision: Car vs Van

  • Thread starter Thread starter superdave
  • Start date Start date
  • Tags Tags
    Momentum
Click For Summary

Homework Help Overview

The discussion revolves around calculating the final velocity of two vehicles, a car and a van, after a completely inelastic collision. The car has a mass of 1500 kg and is traveling east at 25 m/s, while the van has a mass of 3000 kg and is traveling south at 16.7 m/s.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of momentum conservation in both the x and y directions, questioning how to resolve the final velocity components after the collision. Some express uncertainty about needing additional information, such as an angle, to fully understand the resultant velocity.

Discussion Status

Several participants have provided insights into the momentum conservation principles relevant to the problem. There is an ongoing exploration of how to set up the equations for momentum before and after the collision, with no explicit consensus reached on the final approach.

Contextual Notes

Some participants have acknowledged previous misunderstandings regarding the nature of the collision, clarifying that it is completely inelastic, meaning the vehicles stick together post-collision. There is also a recognition of the need to consider the components of momentum separately for accurate calculations.

superdave
Messages
149
Reaction score
3
A car (1500 kg) travels east at 25 m/2. Van (3000 kg) travels south at 16.7 m/s. what is their final velocity after they collide? completely inelastic.

I can't figure it out at all. none of my formulas seem to fit.
 
Physics news on Phys.org
deleted this because I didn't read the post properly :redface:
 
Last edited:
superdave said:
A car (1500 kg) travels east at 25 m/2. Van (3000 kg) travels south at 16.7 m/s. what is their final velocity after they collide? completely inelastic.

I can't figure it out at all. none of my formulas seem to fit.

Completely inelastic means that the objects move with the same velocity after the collision (they get "stuck" together of you will). You have to impose [itex]\sum p_{x,before} = \sum p_{x,after}[/itex] and likewise for the y direction. The two unknowns will be [itex]v_{x,after}[/itex] and[itex]v_{y,after}[/itex].
 
damn!...really sorry about that one...yes they are stuck together (read inelastic as elastic :redface: )
 
But don't I need to know theta in order to figure out how much of x and how much of y there are all together?
 
You know the inital y-momentum (due to the car traveling south). You also know the x-momentum (due to the car traveling east). As they combine on impact, there is only one resultant path, the x and y components of momentum must be equal to the inital x and y components.

I'll try and set it up for you...
(this is as nrqed said, but written in a more explicit way)

[tex]P_{xi} = m_{1}v_{xi}[/tex]

[tex]P_{yi} = m_{2}v_{xy}[/tex]

[tex]P_{xf} = (m_{1} + m_{2})v_{xf} = P_{xi}[/tex]

[tex]P_{yf} = (m_{1} + m_{2})v_{yf} = P_{yi}[/tex]

If you solve these for [itex]v_{yf}[/itex] and [itex]v_{xf}[/itex], you have two velocities which are perpendicular. These can be resolved into a single velcoity using trig. The angle can also be found using trig.

Hope this helps
-Hoot:smile:
 
Last edited:
Lemme try and redeem myself a little :redface: ...You have two vehicles, and you know their weights and speeds...if you look at one vehicle individually you will notice that by considering east and south as the components of velocity this vehicle really only has one component (either east or south)...from this you can say what both vehicles momentums are in either direction (note that if you are focusing on south, the car can be considered at rest, ie: it has no component of it's velocity in this direction)...after collision this momentum is conserved (for each component) but you now have 2 vehicles that move as one (ie: one object), this one object weighs as much as both objects before collision and will now move both east and south. The final speeds in these directions will allow you to find the resultant velocity and hence find [tex]\theta[/tex]

edit...sorry hootenanny didn't see your post
 
GregA said:
edit...sorry hootenanny didn't see your post

Don't worry about it, I'd have left it for you if I'd have known you were still online. Atleast we're all saying the same thing :biggrin:
 

Similar threads

Replies
3
Views
7K
Replies
10
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 13 ·
Replies
13
Views
1K
Replies
57
Views
3K
Replies
9
Views
3K
  • · Replies 5 ·
Replies
5
Views
9K
  • · Replies 9 ·
Replies
9
Views
5K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K