Calculating Final Velocity of 100kg Object Dropped from 100m

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To calculate the final velocity of a 100kg object dropped from a height of 100m, use the principle of conservation of energy. The potential energy at height h is given by mgh, where g is the acceleration due to gravity. As the object falls, this potential energy converts entirely into kinetic energy at ground level. By setting the kinetic energy equal to the initial potential energy, you can solve for the final velocity. The final velocity can be calculated using the formula v = sqrt(2gh).
charlie hogg
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How can I calculate the impact speed(final velocity) of an object of mass 100kg, dropped from a height of 100m, only considering gravity.
 
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Pretty straight forward isn't it? Since you are only considering gravity, total energy is conserved. At height h, the object's potential energy, relative to the ground at height 0, is mgh. Since it is dropped, its velocity and so kinetic energy is 0. At the ground, height 0, its potential energy, relative to height 0, is 0 so all of that potential energy is converted to kinetic energy. Set the formula for kinetic energy equal to mgh and solve for v.
 
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Thread 'Mousetrap Car Energy efficiency'

For simple comparison, I think the same thought process can be followed as a block slides down a hill, - for block down hill, simple starting PE of mgh to final max KE 0.5mv^2 - comparing PE1 to max KE2 would result in finding the work friction did through the process. efficiency is just 100*KE2/PE1. If a mousetrap car travels along a flat surface, a starting PE of 0.5 k th^2 can be measured and maximum velocity of the car can also be measured. If energy efficiency is defined by...
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