- #1

Gixxer99

- 6

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- TL;DR Summary
- The impact of pressure drop on channel inlet when wind flow passing by perpendicular of channel opening.

Hello

I'm thinking of how to attack this problem.

Outside a channel-inlet, wind is passing perpendicular to the opening with a wind speed of 9 m/s and a fan sucks in a certain amount of air into this channel so that the velocity in the channel is 3 m/s.

When the outside air is 0 m/s I have no additional pressure drop that the fan needs to overcome, when entering the channel, when the outside air is a little bit windy = 9 m/s the I get a additional pressure drop of 40 Pa.

What I'm thinking of is how to estimate the additional pressure drop if the 2 velocitys are different, because I'm assuming that channel velocity also needs to be in this equation. If I could convince myself that channel velocity do not have an impact and that only the outdoor velocity has, then I should just derive a K factor from known conditions and do a minor pressure loss calcualtion to estimate new pressure drop to the changed conditions, but I think this is a to big shortcut.

I'm thinking of how to attack this problem.

Outside a channel-inlet, wind is passing perpendicular to the opening with a wind speed of 9 m/s and a fan sucks in a certain amount of air into this channel so that the velocity in the channel is 3 m/s.

When the outside air is 0 m/s I have no additional pressure drop that the fan needs to overcome, when entering the channel, when the outside air is a little bit windy = 9 m/s the I get a additional pressure drop of 40 Pa.

What I'm thinking of is how to estimate the additional pressure drop if the 2 velocitys are different, because I'm assuming that channel velocity also needs to be in this equation. If I could convince myself that channel velocity do not have an impact and that only the outdoor velocity has, then I should just derive a K factor from known conditions and do a minor pressure loss calcualtion to estimate new pressure drop to the changed conditions, but I think this is a to big shortcut.