Calculating Force for 500lb Electric Actuator Door

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Discussion Overview

The discussion centers around calculating the force required for an electric actuator to operate a 500 lb door that raises on an arc. Participants explore the mechanics involved, including lever principles and the implications of the door's design on actuator selection.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Conceptual clarification

Main Points Raised

  • One participant seeks assistance with the calculations needed to determine the appropriate force for an actuator to lift a 500 lb door.
  • Another participant notes that the force required will vary throughout the lift, suggesting that maximum force occurs at the top of the lift due to the lever arm's orientation.
  • A different participant describes the door's motion as more complex than a simple lever, indicating that the design may not lend itself to straightforward calculations.
  • One participant expresses concern about the mechanical advantage of the current design, suggesting it may be inefficient.
  • A participant calculates that approximately 636 lb of force is needed to balance the load, indicating that the existing 1500 lb actuator is sufficient, while also acknowledging the need to consider design improvements.
  • Another participant requests further information on the calculations and design if the original poster has succeeded with the concept.

Areas of Agreement / Disagreement

Participants express differing views on the complexity of the door's mechanics and the efficiency of the design. There is no consensus on the optimal approach or design modifications, and the discussion remains unresolved regarding the best method for calculating the required force.

Contextual Notes

Participants mention varying assumptions about the lever mechanics and the design's efficiency, which may affect the calculations. The discussion does not resolve these assumptions or provide a definitive formula for the force calculation.

Who May Find This Useful

Individuals interested in mechanical design, actuator selection, and force calculations in engineering applications may find this discussion relevant.

RLCOS
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I have a door that weighs 500 lbs. It raises up on an arc. It uses an electric actuator to pull on the lever to raise the door and push to lower. I am modifying the door and do not know how to calculate the force in pounds to make sure I have the right actuator. I currently use a 1500 lb actuator. I need assistance with the equation/formula to come up with an answer. Forgive the typo.
 

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Rather a strange door! If I read this correctly it will move quite a lot backwards and forwards as it lifts.
The force will also vary substantially over the lift.

The maximum force will be required at the top of the lift as the short lever arm becomes almost straight-on to the actuator - in fact at that position the force required is theoretically infinite because it's a lever with a very short (hardly any) leverage. Whatever actuator you use if will simply run out of 'grunt' at some point near the top.

It might be an idea to re-design the mechanism to make it more efficient in the use of leverage.
 
The door actually goes out on the arc and straight up. In the up position the bottom of the door is just above the top of where the door was when in the down position. I think this more than a simple type 1 lever calculation, yes?
 
From the drawing, it looks to me like a simple lever. Maybe I'm wrong to see it that way, my interpretation suggests it's about the worst possible design for mechanical advantage.
 
Thanks A.J. A simple lever calc shows me with about 636 lb force required to balance the load. So my 1500 lb actuator will work. The design actually works pretty well. However your comments give me food for thought and I will certainly look a different design.

I was most likely trying to over think the calc. I do that a lot.
 
Hello,

Have u succeeded with this design concept?
If yes, please help me by posting the calculations and design.
I will be very thankful to you.

Regards,
Dhanesh
 

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