Calculating Force - Intuition vs. Solution

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The discussion revolves around calculating force in a physics problem involving an object in space with a mass of 68 kg, propelled for 3.0 seconds, resulting in a displacement of 2.25 m. The correct force is determined to be 34 N using the formula F = ma, where acceleration is calculated from displacement and time. There is confusion regarding an alternative calculation that yields 17 N, which is identified as a dimensional analysis mistake rather than a valid force calculation. The conversation highlights the importance of including dimensionless constants in dimensional analysis to avoid misinterpretation. Ultimately, understanding the relationship between mass, acceleration, and force is crucial for accurate calculations.
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I'm having a little trouble conceptualizing calculations of force. The problem statement was:
An object in space with a mass of 68 kg is propelled forward at a constant force (\vec{F}) for 3.0 seconds. After 3.0 s, the object has moved 2.25 m. find \vec{F}.

I can regurgitate the proper answer (34 N) by finding a_{x}=2 \Delta x/t^{2} = 0.50 m/s^{2} and \vec{F}=ma_{x} = (68kg)(0.50 m/s^{2}) = 34 N.

the problem is that my intuition tells me that it should be:
t = 3.0s
m = 68 kg
Δx = 2.25 m
So since N = kg \cdot m / s^{2}, N = 68 kg \cdot 2.25 m / 3.0 s^{2} = 17 N, which is obviously wrong. But, does that actually mean something else? Is that some sort of instantaneous value or something, or is it completely meaningless?
 
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What you have done is basically dimensional analysis. When you do this you need to keep in mind that the expression may contain a dimensionless constant, say 'k', which you need to include. Two quantities dimensionally equal aren't necessarily the same.

So, in your case it would be,

F \alpha [M][L][T]^{-2}

Therefore,

F = k * MLT^{-2}

Where the value of k is...? :wink:

...And, I feel good to be able to post again. :biggrin:
 
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