Calculating Force of Static Friction on a Car

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SUMMARY

The discussion focuses on calculating the force of static friction acting on a car with a mass of 1100 kg navigating a corner with a radius of 55 m at a speed of 15 m/s. The initial calculation yielded a static friction force of 300 N, derived from the equation f_s = mv^2/r. However, the expected value for static friction was stated to be 4.5 N, indicating a significant discrepancy in the calculations. The confusion arose from misinterpreting the problem's requirements, which only asked for the force rather than the coefficient of friction.

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  • Understanding Newton's Second Law of Motion
  • Familiarity with centripetal force calculations
  • Knowledge of static friction concepts
  • Basic algebra for solving equations
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  • Review the derivation of centripetal force equations
  • Study the relationship between mass, velocity, and radius in circular motion
  • Learn how to calculate static friction force using f_s = μ_s * N
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Homework Statement


When you take your 1100-kg car out for a spin, you go around a corner of radius 55m with a speed of 15m/s. Assuming your car doesn't skid, what is the force exerted on it by static friciton?

Homework Equations


f[tex]_{}c[/tex]=ma[tex]_{}c[/tex]
f[tex]_{}c[/tex]=mv[tex]^{}2[/tex]/r
[tex]\sumf=ma[/tex]

The Attempt at a Solution


[tex]\sum[/tex]f=ma
f[tex]_{}s[/tex]=mv[tex]^{}2[/tex]/r
f[tex]_{}s[/tex]=300

300=[tex]\mu[/tex][tex]_{}s[/tex]mg
300=[tex]\mu[/tex][tex]_{}s[/tex](1100)(908)
[tex]\mu_{}s[/tex]=0.027

but apparantley it's supposed to be 4.5
what happened?
 
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How did you get 300?

And why are you calculating the coefficient of friction? The question only asks for the force.
 

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