Calculating Gas Pressure: Solving for Pressure in a Variable Volume

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The problem involves calculating the pressure of a gas when its volume changes from 2m^3 to 1.5m^3 while keeping the temperature constant. The initial pressure is 100kPa, but a calculation attempt using a direct proportion led to an incorrect result of 75kPa. The correct pressure is determined to be 133kPa, which can be derived using the ideal gas law, PV = nRT, where the number of moles and temperature remain constant. It's emphasized that when volume decreases, pressure must increase, and careful attention to units and states of the gas is essential for accurate calculations. Understanding the relationship between pressure and volume is crucial in solving such problems.
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Homework Statement


Gas occupies 2m^3 at a pressure of 100kPa. What is the pressure when the volume is 1.5m^3 and the temprature is unchanged?

Homework Equations


p=nRT/V

The Attempt at a Solution


As a logic conclusion i took 1.5/2x100 and got 75 but 175 is not the answer.. The answer is 133kPa.
I also tried the p=nRT/V.
22.4l=1mol so 1500/22.4x1 is 66.96mol. (66.96x22.4x0)/1500=0
Can someone please tell me how to calculate this type of problem?

Thank you.
 
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Bechensten said:

Homework Statement


Gas occupies 2m^3 at a pressure of 100kPa. What is the pressure when the volume is 1.5m^3 and the temprature is unchanged?

Homework Equations


p=nRT/V

The Attempt at a Solution


As a logic conclusion i took 1.5/2x100 and got 75 but 175 is not the answer.. The answer is 133kPa.
I also tried the p=nRT/V.
22.4l=1mol so 1500/22.4x1 is 66.96mol. (66.96x22.4x0)/1500=0
Can someone please tell me how to calculate this type of problem?

Thank you.
Well, your "logic conclusion" got warped somehow.

If you take a certain volume of gas and then shrink that volume, keeping the amount of gas and its temperature constant, what do you think happens to the pressure of the gas confined into that new, smaller volume?

If you analyze the relation PV = nRT, n is the same, R is a constant, and T is the same. So what happens to PV if V gets smaller?
 
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Bechensten said:

Homework Statement


Gas occupies 2m^3 at a pressure of 100kPa. What is the pressure when the volume is 1.5m^3 and the temprature is unchanged?

Homework Equations


p=nRT/V

The Attempt at a Solution


As a logic conclusion i took 1.5/2x100 and got 75 but 175 is not the answer.. The answer is 133kPa.
I also tried the p=nRT/V.
22.4l=1mol so 1500/22.4x1 is 66.96mol. (66.96x22.4x0)/1500=0
Can someone please tell me how to calculate this type of problem?

Thank you.

Always check your units to make sure that what you are calculating makes sense.
You are analyzing the gas in two states.
Start with what you know. What is the pressure and volume of the gas in the first state? What do you know about the second state? I would encourage you to use subscripts. P1 is the pressure of the gas in state 1. P2 is the pressure of the gas in state 2. V1 is the volume of the gas in state 1. etc.
 
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