Calculating Gravity and Mass on Venus: Solve for the Sun's Mass

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Homework Help Overview

The discussion revolves around calculating the acceleration due to gravity on Venus and determining the mass of the Sun based on Venus's orbital characteristics. The problem involves gravitational concepts and ratios related to planetary mass and radius.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the use of gravitational formulas and ratios to compute gravity on Venus without directly calculating its mass and radius. There are attempts to apply the gravitational force equations and ratios of Earth to Venus.

Discussion Status

Some participants have offered alternative approaches to avoid direct calculations of Venus's mass and radius, suggesting the use of ratios instead. There are indications of confusion regarding the application of these ratios, with several participants questioning their calculations and the proper use of units.

Contextual Notes

Participants are working under the constraints of the problem's parameters, including the known mass and radius of Earth, and the specific orbital characteristics of Venus. There are ongoing discussions about the correct application of gravitational formulas and the relationships between the variables involved.

MAPgirl23
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1. The mass of Venus is 81.5% that of the earth, and its radius is 94.9% that of the earth.

Compute the acceleration due to gravity on the surface of Venus from these data.
What is the weight of a 5.00-kg rock on the surface of Venus?

2. Venus orbits the sun in a nearly circular orbit. The radius of the orbit of Venus is 1.08x10^11 m, the period of Venus is 224.7 days(1.94 x 10^7 s)

Calculate the mass of the sun.

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** I know F_grav = m * g and F_grav = GM_Earth*m/d^2

M_Earth = 5.98 x 10^24 kg and R_Earth = 6.38 x 10^6 m

I conclude: M_Venus = 4.88x10^24 kg and R_Venus = 6.06 x 10^6 m

Please help. I'm stuck
 
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It's not necessary and probably not a good idea to calculate the mass and radius of Venus! Instead use ratios.

Basic gravity formula: F= \frac{GmM}{r^2} where G is the "universal" gravitational constant, M the mass of the planet, m the mass of the falling object, and r is the radius of the planet. Since mg= F, g= \frac{GM}{r^2}.
In particular, for the Earth g_e= 9.81 m/s^2= \frac{GM_e}{r_e^2} and for Venus g_v= \frac{GM_v}{r_v^2}.

Divide the second equation by the first and the "G" terms cancel:
\frac{g_v}{9.81}= \frac{M_v}{M_e}\left(\frac{r_e}{r_v}\right)^2. You are given those ratios.
 
Last edited by a moderator:
but I did: g_v = [(M_v*r_v^2)/(M_e*r_e)]*9.81 = 4.60 x 10^7 m/s^2

what did I do wrong?
 
oh, I see now
 
but I did [(M_v*M_e)/(r_v*r_e)^2]*9.81 = 7.22 m/s^2 what did I do wrong?
 
Check the units in that [].They don't match.

Daniel.
 
[(M_v/M_e)*(r_v*r_e)^2]*9.81 = 7.22 m/s^2

[(4.88x10^24 kg/5.98x10^24 kg)*(6.06x10^6 m*6.38x10^6 m)^2]*9.81 = 7.22 m/s^2
 
sorry it was [(4.88x10^24 kg/5.98x10^24 kg)*(6.06x10^6 m/6.38x10^6 m)^2]*9.81 = 7.22 m/s^2
 
that got me 0.816 * 0.902 * 9.81 = 7.22
 
  • #10
MAPgirl23 said:
sorry it was [(4.88x10^24 kg/5.98x10^24 kg)*(6.06x10^6 m/6.38x10^6 m)^2]*9.81 = 7.22 m/s^2

The problem is in the bold part:
[(4.88x10^24 kg/5.98x10^24 kg)*(6.06x10^6 m/6.38x10^6 m)^2]*9.81 = 7.22 m/s^2

You are dividing Venus' radius by the Earth's radius, and you should be dividing the Earth's radius by Venus' radius.
 

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