Calculating Heat Exchange for a Water Pump

Click For Summary
To calculate the heat exchange required for a water pump operating at 10 W, raising the pressure of water from 1 bar to 2 bar while maintaining a constant temperature of 25°C, the first law of thermodynamics should be applied rather than the ideal gas law. The discussion emphasizes that the problem involves an open system, where energy conservation principles are crucial. The user expresses confusion over the necessary parameters, such as volume and moles, indicating a lack of clarity in setting up the equations. Understanding the relationship between work done by the pump and heat exchange with the surroundings is essential for solving the problem. Accurate calculations will yield the required heat exchange to maintain the system's steady state.
rachel6589
Messages
1
Reaction score
0

Homework Statement


A pump, operating at 10 W, is used to raise the pressure of a stream of water at 2.5 mol/s from 1 bar to 2 bar. At steady state, if the water temperature should remain constant at 25oC, how much heat exchange between the pump and its surroundings is required? Note that 1 bar = 105 Pa and C liq,water = 4.18 J g-1 K -1

Homework Equations


PV=NRT

The Attempt at a Solution


I tried to set up two equations. The first one is (1)(V)=NR(373+25) and the second is (2)(V)= NR(373+25)
and I don't know find out the heat exchange since there are some unknown data( Volume? Mole?)
[/B]
 
Physics news on Phys.org
rachel6589 said:

Homework Statement


A pump, operating at 10 W, is used to raise the pressure of a stream of water at 2.5 mol/s from 1 bar to 2 bar. At steady state, if the water temperature should remain constant at 25oC, how much heat exchange between the pump and its surroundings is required? Note that 1 bar = 105 Pa and C liq,water = 4.18 J g-1 K -1

Homework Equations


PV=NRT

The Attempt at a Solution


I tried to set up two equations. The first one is (1)(V)=NR(373+25) and the second is (2)(V)= NR(373+25)
and I don't know find out the heat exchange since there are some unknown data( Volume? Mole?)[/B]
The solution to this problem has nothing to do with the ideal gas law. This is a problem in application of the open system (control volume) version of the first law of thermodynamics.
 
Last edited:
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
22
Views
4K
Replies
3
Views
1K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
4
Views
2K
Replies
1
Views
3K