Calculating Heat Needed to Melt Metal

  • Thread starter Thread starter Weave
  • Start date Start date
  • Tags Tags
    Heat Metal
Click For Summary

Homework Help Overview

The discussion revolves around calculating the heat required to melt a metal, considering its mass, initial temperature, heat capacity, and melting point. Participants are exploring the concepts of heat transfer and phase changes in the context of thermodynamics.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the formula for calculating heat, with initial attempts focusing on the energy needed to raise the temperature to the melting point. There is a shift towards considering the latent heat required for the phase change from solid to liquid.

Discussion Status

Some participants have offered clarifications regarding the need to account for both the temperature change and the phase change in the calculations. There is an ongoing exploration of the implications of these factors, with no clear consensus reached on the final approach.

Contextual Notes

There is a recognition that the problem may not be fully answerable without additional information, specifically the latent heat value. Participants are questioning the assumptions made in their calculations.

Weave
Messages
143
Reaction score
0

Homework Statement


Ok this one is easy I just want to make sure:
A metal of mass M is in a smelter at temperature T_{o}.
How much heat does it take to melt the metal. Given: heat capacity, melting point T_{m}


Homework Equations


Q=Mc\Delta T

The Attempt at a Solution


So it would be simply
Q=Mc(T_{m}-T_{o})
Right?
 
Physics news on Phys.org
That's just the energy required to heat the metal up to the melting point, what about the actual phase change (i.e. latent heat)?
 
so \frac{Q}{M}=L Q being the previous answer from Q=Mc\Delta T
 
it should be Q=Mc\Delta T + ML if you melt solid to liquid

Q=Mc\Delta T (unchange state)
Q=ML (change state)
 
Weave said:
so \frac{Q}{M}=L Q being the previous answer from Q=Mc\Delta T

So I am incorrect?
 
Weave said:
so \frac{Q}{M}=L Q being the previous answer from Q=Mc\Delta T
Q isn't necessarily that from the previous answer.
 
so..what I am I looking for?
 
Weave said:
so..what I am I looking for?
I'd be tempted to say that the question isn't answerable unless your given L; but I'm willing to learn...
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
11
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
7
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
23
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K