Calculating Heat Transfer (Thermal Radiation) to a Shipping Container

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SUMMARY

The discussion focuses on calculating thermal radiation heat transfer to a shipping container painted white, with dimensions of 4.636 m x 2.591 m x 2.438 m, resulting in a maximum surface area of 29.6 m². The initial calculation using the Stefan-Boltzmann Constant yielded 1953 W, but was deemed inappropriate for the context. A subsequent calculation using nominal irradiance and an emissivity value of 0.4 resulted in a high estimate of 3584 W, highlighting the need for a more nuanced approach that considers solar geometry and location specifics. The user seeks guidance on accurate equations or resources for achieving a target internal temperature of 30 degrees Celsius.

PREREQUISITES
  • Understanding of thermal radiation principles
  • Familiarity with the Stefan-Boltzmann Constant
  • Knowledge of emissivity values and their implications
  • Basic concepts of HVAC systems and heat transfer calculations
NEXT STEPS
  • Research solar geometry and its impact on heat transfer calculations
  • Learn about advanced HVAC load calculation methods
  • Explore the use of thermal modeling software for accurate simulations
  • Investigate the effects of different surface coatings on thermal performance
USEFUL FOR

HVAC engineers, thermal engineers, and anyone involved in designing climate control systems for shipping containers or similar structures.

thomas82
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Hello,

I am trying to calculate the thermal radiation heat transfer to a shipping container which would be painted white.

The purpose is to size an air conditioner for equipment, not living conditions. I have already calculated heat from the other sources. The desired internal temperature is 30 degrees.

The container has dimensions 4.636 m x 2.591 m x 2.438 m (There is an internal wall) which implies three sections could face the sun at any given time, for a maximum surface area of 29.6 m2

On my first attempt I used an equation based on the Stefan-Boltzmann Constant:

Q = ε σ (Th4 – Tc4) A

The amount I calculated was 1953 W, But I've been told this equation is invalid in this context.

On my second attempt I used the nominal irradiance and just the roof area. I used an emissivity value of 0.4.

800 W/m2 x 11.2m2 x 0.4 = 3584 W

This value is very high and the process is hugely simplistic given that I'm ignoring solar geometry and the specifics of the location entirely. Also, the intention is not to remove all the heat, but I can't figure out how to separate it into a component which would allow for 30 degrees worth of heat to remain.

Can anyone direct me to a site (or provide the step by step equations) that could lead to a reasonable approximation for this application? You're also welcome to comment on how I've approached the problem.

Thank you,

Thomas
 
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