A double covalent bond of nitrogen (N2) is 15.58eV Now lets go into a example. if i have a laser that is 477nm and i do 1240/477nm then i get 2.6eV per photon.(adsbygoogle = window.adsbygoogle || []).push({});

Now if i do (15.58eV / 2.6eV) it equals ~6 photons.

Now to figure out how many Joules are required for 1 photon I do

(6.626*10^-34S * 3.00*10^17nm/s) / 477nm which equals 4.167e-19 J, and for 6 photons thats 2.5002e-18 J.

Now if i want to get 6 photons in a pulse then I would need 2.5002e-18 J right? Now that is in Joules i need per nanosecond, which is 2.5002e-9 watts. All i want to know is why does it require such low amounts of energy to do this, when all i see is that you need ALOT of watts to ionize. Now as i was typing this i thought that maybe that equation shows how many joules of energy are in each photon, but yet this video

says "Joules required per photon". But if this equation is not right then what equation should i use.

(also this is my first time on this forum so if anything is wrong or im not in the right place let me know thank you)

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# I Calculating how many Joules are required to make a photon

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