The discussion revolves around calculating the internal resistance of a series battery circuit formed by four 1.5 V cells. An external resistor of 31 Ohms is connected, and the current measured is 280 mA. Participants are attempting to find the internal resistance of each cell based on the provided information.
The discussion is ongoing, with participants raising concerns about the validity of the problem setup and the calculations presented. Some suggest that the given values do not seem to fit together logically, indicating a potential issue with the problem statement itself.
There is uncertainty regarding the accuracy of the provided current value and the implications of the external resistance in relation to the calculated total resistance. Participants express a need to clarify the question with the lecturer due to perceived inconsistencies.
helper- said:1. V = E - Ir ?
helper- said:R = e / i = 6V / 0.290A = 21.43 Ohms
**is this is less than the load resistance of 31 Ohms?
The answer given is 0.19 Ohms; but unable to solve. Any idea?
truesearch said:something wrong here ! 6V emf, current of 0.28A means total R = 6/0.28 =21.4 ohms
Does not fit with external resistance of 31 ohms connected.
Check the question