Calculating Iout & Output Resistance of BJT-MOSFET Circuit

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The discussion focuses on calculating Iout as a function of Vc2 and determining the output resistance for a specific condition in a BJT-MOSFET circuit. Participants clarify that VDD typically represents a positive DC supply voltage, while VA refers to the Early voltage, emphasizing that VA is not a typo for VDD. The consensus is that the exact value of VDD is less critical due to the presence of a current source in series, which simplifies circuit analysis. This current source is often modeled as a transistor network in practical applications. Understanding these parameters is essential for accurate circuit analysis and design.
etf
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Hi!
Here is my task:
a) Calculate and sketch Iout=f(Vc2), for 0<Vc2<1.5V. (neglect Early effect)
b) calculate output resistance for Vc2=Vc1.
BJT's Q1 and Q2 are in forward active mode, have identical characteristics and same temperature. MOSFET M3 is in saturation. Iin=10μA, Vt=25mV, Vc1=1.25V, VA=50V.

vdd.jpg


My question is, what does VDD represent? There are few examples in my book where VDD is connected to some current source like this...
 
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VDD will be a +ve DC supply voltage. Your text refers to VA =50V. My guess is this is a typo and VDD is meant to be VA?
 
I don't think so. VA is Early voltage.
 
Generally with questions like this VDD is the biasing voltage source that puts the amplifer into the active region. My prof always used VCC for it :)
 
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etf said:
I don't think so. VA is Early voltage.

I think you're right.

The actual value of VDD isn't really important in this circuit as there is a current source in series.
 
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In real life that current source will be a transistor network. It it frequently represented as a current source to simplify analysis.
 
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