Calculating Iterated Integrals - 2e4

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Homework Help Overview

The problem involves calculating iterated integrals of the form ∫02 dy ∫0yy2 * exy dx, with participants discussing the steps taken in the integration process and the correctness of their approaches.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to evaluate the iterated integral and are questioning the steps taken in their calculations. Some express confusion about the integration process and the application of limits.

Discussion Status

There is ongoing discussion with participants providing feedback on each other's attempts. Some have pointed out potential errors in the integration steps, while others are seeking clarification on specific parts of the process. Multiple interpretations of the steps are being explored.

Contextual Notes

Some participants mention skipping steps in their calculations, and there are indications of confusion regarding the application of limits and the structure of the integrals. The original problem statement is reiterated, but there is no consensus on the correct approach yet.

Kork
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1. The problem statement, all variables and given/known data

Calculate the given iterated integrals ∫02 dy ∫0yy2 * exy dxMy attempt:

20dy[exy*y]y0

= ∫20 ey*y*y - ex*0*0

= ∫20ey2*y dx

= [ey^2]*y]20 = 2e4

Is this correct?
 
Last edited:
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Kork said:
1. The problem statement, all variables and given/known data

Calculate the given iterated integrals ∫02 dy ∫0yy2 * exy dx
I think you skipped a step going from the above to the line below. Written in a more usual form, your integral would be
\int_{y = 0}^2~\int_{x = 0}^y y^2 e^{xy}~dx~dy

(You can see what I did in LaTeX by clicking the integral above.)
Show how you get from the step above to the step where you've carried out the inner integration.


Kork said:
My attempt:

20dy[exy*y]y0

= ∫20 ey*y*y - ex*0*0

= ∫20ey2*y dx

= [ey^2]*y]20 = 2e4

Is this correct?

No - see above. I get (1/2)e4 - 5/2
 
I don't understand what I have done wrong at all
 
The error is here:
\left . ye^{xy}\right |_{x = 0}^y

You need to replace x by 0, not y.
 
Im still confused I get:

[ey^2*y-y]20 =

(e^2^2 - 2) - (e^0^2 - 0) =

2e^4 - 2 ?

Im lost
 
You're skipping steps. You have the outer integrand right, but you have made a mistake when you integrated this integral.
\int_0^2 (ye^{y^2} - y)dy

Split this into two integrals and carry out the two integrations.
 
Last edited:
Oh I have totally lost my comprehensive view now...
 
Kork said:
Oh I have totally lost my comprehensive view now...
I don't know what you mean by this.
 
How do I get from:

= ∫(y = 0 to 2) (ye^(y^2) - y) dy

= (1/2)e^(y^2) - (1/2)y^2 {for y = 0 to 2}

?
 
  • #10
y0 ye^(y^2) - y dy

to

= (1/2)e^(y^2) - (1/2)y^2


{for y = 0 to 2}
 
  • #11
Split the integral into two.
Use substitution to do the first integral.
 
  • #12
This didnt get me further from start, but thanks anyway.
 
  • #13
Kork said:
y0 ye^(y^2) - y dy

to

= (1/2)e^(y^2) - (1/2)y^2
When you evaluate the above at 2 and 0, what do you get?

Sorry, I misunderstood what you were asking before.
Kork said:
{for y = 0 to 2}
 

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