Calculating Kp for a Gas-Phase Equilibrium Reaction

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Discussion Overview

The discussion revolves around calculating the equilibrium constant Kp for the gas-phase reaction involving xenon (Xe) and fluorine (F2) to form xenon tetrafluoride (XeF4). Participants explore the initial and equilibrium pressures of the reactants and the implications for determining Kp.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Conceptual clarification

Main Points Raised

  • One participant presents the initial pressures of Xe and F2 and expresses confusion about calculating Kp, suggesting an initial formula.
  • Another participant questions the fate of the remaining Xe at equilibrium, indicating a need for clarification.
  • Some participants speculate that the remaining Xe may have left the container, while others suggest it has reacted to form XeF4.
  • Participants discuss the need to determine the partial pressures of all species at equilibrium to accurately calculate Kp.
  • There is a prompt to compare the expression for Kp with the balanced reaction equation provided.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the calculation of Kp, and there are multiple competing views regarding the behavior of Xe at equilibrium.

Contextual Notes

Participants have not fully established the assumptions regarding the reaction extent or the stoichiometry involved in the equilibrium calculation.

Who May Find This Useful

Students or individuals interested in gas-phase equilibrium reactions and the calculation of equilibrium constants in chemistry.

rcrx
Messages
16
Reaction score
0
A reaction mixture initially contains 2.24 atm Xe and 4.27 atm F2. If the equilibrium pressure of Xe is 0.34 atm, determine Kp for the reaction.

This question came out of the blue, and all I can think of is that Kp=(PXe)(PF2), but the answer is supposed to be 25.

I don't get it? Any suggestions? Thanks!
 
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Initial pressure of Xe was 2.24 atm, at equilibrium it was 0.34 atm. What have happened to the rest of Xe?

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methods
 
It must have left the container? I don't know, really :\
 
Question asks about reaction equilibrium constant... What reaction?

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Oh, sorry. Xe(g) + 2F2(g) ---> XeF4(g)
 
So again, what happened to the rest of the Xe?
 
The rest of Xe has gone to the formation of XeF4
 
Can you now figure out the partial pressures of all species at equilibrium?

And take another look at the expression you have for Kp (compare with the equation in post#5).
 

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